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3: Relative motion analysis (translating axes)

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Relative Motion Analysis (Translating Axes)

In particle kinematics, relative motion analysis using translating axes simplifies problems where multiple objects move independently. This method isolates the motion of one particle relative to another by attaching a moving coordinate system (frame) to a reference particle. Crucially, the frame translates but does not rotate, meaning its axes remain parallel to the fixed global axes.

Key Concepts
  1. Position Vectors:

    • Let rA\vec{r_A} and rB\vec{r_B} be the positions of particles AA and BB relative to a fixed frame OO.
    • The position of AA relative to BB is rA/B=rArB\vec{r_{A/B}} = \vec{r_A} - \vec{r_B}.
  2. Velocity Relationship:

    • The velocity of AA is vA=vB+vA/B\vec{v_A} = \vec{v_B} + \vec{v_{A/B}}, where:
      • vB\vec{v_B}: Velocity of reference particle BB.
      • vA/B\vec{v_{A/B}}: Velocity of AA as observed from the translating frame attached to BB.
    • Since axes translate without rotation, vA/B\vec{v_{A/B}} is the derivative of rA/B\vec{r_{A/B}} in the moving frame.
  3. Acceleration Relationship:

    • Similarly, aA=aB+aA/B\vec{a_A} = \vec{a_B} + \vec{a_{A/B}}, where:
      • aB\vec{a_B}: Acceleration of BB.
      • aA/B\vec{a_{A/B}}: Acceleration of AA measured from BB’s frame.
Why Translating Frames?
  • No Rotational Terms: Because axes remain parallel, angular velocity (ω\vec{\omega}) and angular acceleration (α\vec{\alpha}) do not appear. This simplifies equations: vA/B=rA/B˙,aA/B=rA/B¨\vec{v_{A/B}} = \dot{\vec{r_{A/B}}}, \quad \vec{a_{A/B}} = \ddot{\vec{r_{A/B}}}
  • Intuitive Analysis: Imagine a boat (AA) crossing a river with flowing water (BB). The boat’s velocity relative to water is vA/B\vec{v_{A/B}}, while the river’s flow is vB\vec{v_B}.
Problem-Solving Strategy
  1. Identify reference particle BB and attach a translating frame to it.
  2. Express vB\vec{v_B} and aB\vec{a_B} in the fixed frame.
  3. Compute vA/B\vec{v_{A/B}} or aA/B\vec{a_{A/B}} using kinematics (e.g., derivatives if rA/B\vec{r_{A/B}} is given).
  4. Apply: vA=vB+vA/B,aA=aB+aA/B\vec{v_A} = \vec{v_B} + \vec{v_{A/B}}, \quad \vec{a_A} = \vec{a_B} + \vec{a_{A/B}}
Example

Two cars AA and BB move on straight roads. Given vB=10 m/s i^\vec{v_B} = 10\ \text{m/s} \ \hat{i} and vA/B=5 m/s j^\vec{v_{A/B}} = -5\ \text{m/s} \ \hat{j} (indicating AA moves south relative to BB):

  • vA=10i^5j^ m/s\vec{v_A} = 10\hat{i} - 5\hat{j}\ \text{m/s}.

Common Exam Focus:

  • Vector subtraction to find rA/B\vec{r_{A/B}}, vA/B\vec{v_{A/B}}, or aA/B\vec{a_{A/B}}.
  • Applications like aircraft in wind or particles on moving platforms.
  • Remember: Translating frames only—rotation introduces Coriolis terms (covered later).