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6: Dielectrics

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Ethan Moore

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Ethan Moore

2,298 pts

5 days ago

Choose your name

Ethan Moore

Your opponent is

Ethan Moore

2,298 pts
5 days ago
The quiz will be on the following text — learn it for the best chance to win.
Section 1: Electrostatics
6: Dielectrics

Dielectrics are insulating materials (e.g., glass, plastic) that exhibit no free charges but polarize in an external electric field. Unlike conductors, they lack mobile charges, but their bound charges (electrons bound to atoms/molecules) redistribute under an applied field, reducing the net field within the material.

Polarization
When an external field E0\mathbf{E}_0 acts on a dielectric, it induces polarization:

  • Nonpolar molecules (e.g., CH4\text{CH}_4) develop induced dipole moments as electron clouds shift relative to nuclei.
  • Polar molecules (e.g., H2O\text{H}_2\text{O}) experience alignment of permanent dipoles with the field.
    The net effect is a volume distribution of bound charges. Polarization P\mathbf{P} (dipole moment per unit volume) is defined as:
P=χeε0E\mathbf{P} = \chi_e \varepsilon_0 \mathbf{E}

where χe\chi_e is the electric susceptibility, and E\mathbf{E} is the net field inside the dielectric.

Dielectric Constant & Capacitance
The relative permittivity (dielectric constant) κ1\kappa \geq 1 quantifies a dielectric’s ability to reduce E\mathbf{E}:

κ=εε0=1+χe\kappa = \frac{\varepsilon}{\varepsilon_0} = 1 + \chi_e

Here, ε\varepsilon is the permittivity of the material, and E=E0κ\mathbf{E} = \frac{\mathbf{E}_0}{\kappa}.
In capacitors, inserting a dielectric between plates:

  • Increases capacitance: C=κC0C = \kappa C_0 (where C0C_0 is vacuum capacitance).
  • Reduces potential difference for fixed charge: V=V0κV = \frac{V_0}{\kappa}.

Gauss’s Law in Dielectrics
Polarization creates bound surface charges σb=Pn^\sigma_b = \mathbf{P} \cdot \hat{\mathbf{n}}. Gauss’s law modifies to:

\oint \mathbf{D} \cdot d\mathbf{a} = Q_{\text{free}}}

where D=ε0E+P=εE\mathbf{D} = \varepsilon_0 \mathbf{E} + \mathbf{P} = \varepsilon \mathbf{E} is the electric displacement field, and Q_{\text{free}}} excludes bound charges.

Boundary Conditions
At a dielectric interface:

  1. Normal component: D1=D2D_{1\perp} = D_{2\perp} (if no free surface charge).
  2. Tangential component: E1=E2E_{1\parallel} = E_{2\parallel}.

Key Implications

  • Energy density in a dielectric: u=12εE2u = \frac{1}{2} \varepsilon E^2.
  • Dielectric breakdown occurs at a critical field strength, limiting practical voltage.